You want: (Achievable with virtual inheritance)
A
/ \
B C
\ /
D
And not: (What happens without virtual inheritance)
A A
| |
B C
\ /
D
Virtual inheritance means that there will be only 1 instance of the base A
class not 2.
Your type D
would have 2 vtable pointers (you can see them in the first diagram), one for B
and one for C
who virtually inherit A
. D
's object size is increased because it stores 2 pointers now; however there is only one A
now.
So B::A
and C::A
are the same and so there can be no ambiguous calls from D
. If you don't use virtual inheritance you have the second diagram above. And any call to a member of A then becomes ambiguous and you need to specify which path you want to take.
Problematic:
struct Animal {
virtual ~Animal() { }
virtual void eat();
};
struct Mammal : Animal {
virtual void breathe();
};
struct WingedAnimal : Animal {
virtual void flap();
};
// A bat is a winged mammal
struct Bat : Mammal, WingedAnimal {
};
Bat bat;
Solution:
struct Animal {
virtual ~Animal() { }
virtual void eat();
};
// Two classes virtually inheriting Animal:
struct Mammal : virtual Animal {
virtual void breathe();
};
struct WingedAnimal : virtual Animal {
virtual void flap();
};
// A bat is still a winged mammal
struct Bat : Mammal, WingedAnimal {
};